wire configuration

[twink 0]

is this the right configuration to achieve a 1 ohm load?

[shizzzon 461]

i dont own a sundown 1500d but if they use 2 + and - speaker terminals, then they are internally bridged together basically for the sake of easier wiring capabilities.

So... if this is true, if u are trying to hookup just 1 dual 2 ohm sub to your amp, you would run each wire to each terminal...

So on your sub, the + and - of one side would wire to the + and - on the amp and the + and - of the other side of the sub would run to other set of + and - to the amp.

While you do not absolutely need to use all terminals on the amp, if you do not, the resistance must already be 1 ohm once connected to the amp. Otherwise, you run each coil to the amp which is 2 ohms per side, but internally bridged parallels it down to 1 ohm.

[Bobaflob 0]

is this the right configuration to achieve a 1 ohm load?

My MTX TA81001 has 2 terminals like that and thats how it says to hook it up.

[twink 0]

i dont own a sundown 1500d but if they use 2 + and - speaker terminals, then they are internally bridged together basically for the sake of easier wiring capabilities.

So... if this is true, if u are trying to hookup just 1 dual 2 ohm sub to your amp, you would run each wire to each terminal...

So on your sub, the + and - of one side would wire to the + and - on the amp and the + and - of the other side of the sub would run to other set of + and - to the amp.

While you do not absolutely need to use all terminals on the amp, if you do not, the resistance must already be 1 ohm once connected to the amp. Otherwise, you run each coil to the amp which is 2 ohms per side, but internally bridged parallels it down to 1 ohm.

its moved, sorry mods.

back to topic.

if it's internally bridged, this will be more simple. and the amp will see a 1 ohm load?

[fredridge 0]

nice pic.... I wish I was better at that stuff.... took me like 6 tries to make a diagram for a friend

[KU40 173]

wire it whichever way is easier. it's all the same in the end.