///M5

Perhaps teh potential energy of a skier in a frictionless, oh that's right frictionless doesn't exist. Stupid conservation laws applied in unreal circumstances,.

Ouch, my drilled ones were $72 ea stock Bm'er ones are more than $300 per rotor. My understanding with the cross drilled is that the ones that are crack prone are standard rotors that have been drilled, where the Zimm's supposedly are designed to be drillled. I guess we shall see.

If pennis is a driveway....

If you've got the space which you do and the skills I love the idea.

looks great, like the triangle ports. are you going to cover/paint it?

86 the box and you save weight, but to run IB you need to really seal stuff off.

Can't believe it changed that s to a c???

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chitton in my hair.

Got sand on your pennis?

Sorry Kent

At this point my searching is better than my logic when it comes to classical. Basically it is just a conservation of energy question: add up the Kinetic and potential at both angles and set them equal to each other and bang. You can copy from here: http://web.mit.edu/8.01X/www/probsets/sol8...20snowball'

I will seat them tomorrow as I have to let the paint dry.

bump just in case you missed it I can surely try, and somehow I missed that... thanks A skier starts at the top of a very large, frictionless snowball, with a very small, initial speed, and skis straight down the side. At what point does she lose contact with the snowball and fly off tangent? That is, at the instant she loses contact with the snowball, what angle a does a radial line from the center of the snowball to the skier make with the verticle? i dont even know where to begin By definition tangent is 90 degrees. Sounds like a trick question. i know it's not 90 degrees the skier has a horizontal velocity component as she goes down the ball so that would make her fly off before she reaches 90 degrees Missed the word "radially"

bump just in case you missed it I can surely try, and somehow I missed that... thanks A skier starts at the top of a very large, frictionless snowball, with a very small, initial speed, and skis straight down the side. At what point does she lose contact with the snowball and fly off tangent? That is, at the instant she loses contact with the snowball, what angle a does a radial line from the center of the snowball to the skier make with the verticle? i dont even know where to begin By definition tangent is 90 degrees. Sounds like a trick question.

I need to shower first though, will be back in 10. PM me if you like...

bump just in case you missed it I can surely try, and somehow I missed that...

Here is a typical afternoon working on a car. I wear gloves all day, except when I put a wrench on an allen head that slips and I bash my finger. I wear gloves all day, but take them off to stir up the caliper paint and of course spill black paint on my hands. Took my hat off to slide under the car, right into a pile of sand so my hair is full of it. And of course, one of the rotor retaining screws wouldn't turn. Effin' had to drill the beyotch out. Slowed me down a good half hour. Also put in new plugs, fuel filter, air filter and did an oil change. I didn't get around to installing the short shift kit or doing the transmission juice cuz I had to finish the effin' leaves. Not bad considered I put in a good 7 hours of work at work today too. /rant

and put it on twenty fo's? The shot of it without wheels makes me think...pshh, just another BMW up on blocks It looks plain without the rims and lowered stance, actually sort of a plain car which is why I painted the calipers black.

I am not tracking the car, I expect the German parts to last. They were highly recommended. I was just going to go with a normal Brembo, but since the M community liked these I thought wtf.

Brake job's don't deserve threads....

Porsche 959 Paris-dakar style

And lastly, the dirty but installed rim:

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