-
Content Count
4,549 -
Joined
-
Last visited
-
Days Won
54
Content Type
Profiles
Forums
Gallery
Everything posted by Quentin Jarrell
-
42 inch plasma. Charged him 4,800 in labor
-
kinda like so.
- 5 replies
-
- Subwoofer box
- Ported Box
-
(and 1 more)
Tagged with:
-
I pre paint mine first.
- 5 replies
-
- Subwoofer box
- Ported Box
-
(and 1 more)
Tagged with:
-
RA is a side effect of Lupus and I have dime sized arthritus in both my knees. I normally work out and ride a road bike 25-50 miles a week to keep myself moving. Although I've had a bad stint of migraines for a few weeks and spent a week in the hospital. But I'm been feeling good and today is my 2nd day working out and picked up my Advanced SL 0 from the bike shop today so I'm gonna ride a few miles tomorrow.
-
I got damn good insurance and a autoimmune disorder. So I keep track of all Hematology Type 1, or RA? I have psoriosis, some form of arthritis and recently found to be diabetic. Hoping not type 1, but it is what it is. Lupus
-
And sugar is actually classified as a toxin.
-
I got damn good insurance and a autoimmune disorder. So I keep track of all Hematology
-
I have seen in all the blood tests I've had done over the past year(every 6 weeks) that all my vitamin levels stay in the upper 3/4 of what they consider normal. Now this is with me eating at least 4-5 thousand calories a day and taking a multi vitamin. The only thing that is usually low is my mg levels which is contributed to my high creatine levels when taking creatine which normally runs around 1.25 (normal is .63-1.13 ). Another thing to watch is water intake. They really mean it when they say drink at least a gallon of water a day. I have seen my glomerular fltration rates go from 110 to 82 from not taking in enough water. The vitamins I have taken that makes me feel really good though is vitamin B2 and B12. I take a 200mg B2 pill and a 400mg B12 injection daily for migraines but also gives me a great boost of energy through out the day.
-
not a bad way to get 300 amps from a 110 outlet. The largest power supply you can run is 60 amps without running 220 volts
-
High quality USB
Quentin Jarrell replied to arctictwist's topic in Amplifiers / Head Units / Processors / Electrical
GOOGLE can find anything. http://www.amazon.com/gp/aw/d/B003LEMQCM -
No that's ok. As stated in the terms of agreement when one signs up for this site we condemn the advertisement of an unorthorized vender weather it be by the company itself, their dealers, or a "competitor" that can send someone to the "right people".
-
I assume you are a dealer for these companies.
-
That box with the display must be one bad mofo if it can differentiate box rise and impedance rise caused from frequency change and inductance and heat.
-
Klippel LSI with the auralization technique is the only testing Ill pay any attention to. To many flaws in these "tests"
-
Zcon 18" running 1200rms now, 2400 rms worth it?
Quentin Jarrell replied to darren700's topic in Subwoofers / Speakers
It's a hell of a long process to do it by hand but you can use the below equations to figure by hand. SI (mks) units. ^ denotes exponentiation. LOG() is base 10. 5.1 Constants pi = 3.14159265359 c = speed of sound in air (345 m/s) Ro = density of air (1.18 kg/m^3) 5.2 Closed-Box Systems Vb = Vas/Vr Fb = Qr*Fs F3dB = Qr*Fs*((1/Qb^2-2+((1/Qb^2-2)^2+4)^0.5)/2)^0.5 Fmax = c/(pi*0.83*Dia) dBpeak = 20*LOG(Amax) Par = K1/Amax^2 Per = Par/(Gno) Gno = 10^((SPL-112)/10) PeakSPL = SPL+10*LOG(PEmax) Sd = pi*(Dia*0.83)^2/4 Vd = Sd*xmax Amax = Qb^2/(Qb^2-0.25)^0.5 for Qb >(1/2)^0.5, 1 otherwise K1 = (4*pi^3*Ro/c)*Fb^4*Vd^2 K2 = 112+10*LOG(K1) Vr = Qr^2-1 Qr = (1/Qts)/(1/Qb-0.1) Frequency-dependent equations: Fr = (F/Fb)^2 dBmag = 10*LOG(Fr^2/((Fr-1)^2+Fr/Qb^2)) Pmax = K1*((Fr-1)^2+(Fr/Qb^2))/(Gno) SPLmax = K2+40*LOG(F/Fb) Thermally-limited RMS SPL = PeakSPL+dBmag 5.3 Ported Box Systems Vb = 20*Qts^3.3*Vas Fb = (Vas/Vb)^0.31*Fs F3dB = (Vas/Vb)^0.44*Fs Fmax = c/(pi*0.83*Dia) dBpeak = 20*LOG(Qts*(Vas/Vb)^0.3/0.4) Par = 3*F3dB^4*Vd^2 Per = Par/(Gno) Gno = 10^((SPL-112)/10) PeakSPL = SPL+10*LOG(PEmax) Dmin = (Fb*Vd)^0.5 Lv = 2362*Dv^2/(Fb^2*Vb)-0.73*Dv Sd = pi*(Dia*0.83)^2/4 Vd = Sd*xmax K1 = (4*pi^3*Ro/c)*Fs^4*Vd^2 K2 = 112+10*LOG(K1) Frequency-dependent equations: Fn2 = (F/Fs)^2 Fn4 = Fn2^2 A = (Fb/Fs)^2 B = A/Qts+Fb/(7*Fs) C = 1+A+(Vas/Vb)+Fb/(7*Fs*Qts) D = 1/Qts+Fb/(7*Fs) E = (97/49)*A dBmag = 10*LOG(Fn4^2/((Fn4-C*Fn2+A)^2+Fn2*(D*Fn2-B)^2)) Pmax = (K1/Gno)*((Fn4-C*Fn2+A)^2+Fn2*(D*Fn2-B)^2)/(Fn4-E*Fn2+A^2) SPLmax = K2+10*LOG(Fn4^2/(Fn4-E*Fn2+A^2)) Thermally-limited RMS SPL = PeakSPL+dBmag -
Zcon 18" running 1200rms now, 2400 rms worth it?
Quentin Jarrell replied to darren700's topic in Subwoofers / Speakers
Depending on the variables, yes and no. It's going to come down to what environment the driver was designed to work in. If the sub's motor was designed to push the cone to xmax at 2400 watts in say a 5 ft box tuned to 32 hertz then you really wouldn't see that much power compression bc the sub has enough motor force to push it that far in that environment. But then take that same sub and put it in a 3 foot box and then you run into major compression bc the sub just doesn't have enough motor to compensate for the increased "spring" the box is holding onto the sub. This is fairly easy to calculate using SpeaD. And is how I go about determining how much motor force I need for a given xmax in a given volume at a given tuning frequency. In other words if the sub has enough motor for his box and tuning and he is only at half xmax it would be the same as just having your headunit volume at half way. But on the other hand if like impious said if you are already at that point where you the sub just doesn't have any more umph to it then more power will just be wasted as heat. But as a money stand point 1,200 is a lot just for another 15mm xmax. -
Zcon 18" running 1200rms now, 2400 rms worth it?
Quentin Jarrell replied to darren700's topic in Subwoofers / Speakers
The question to be answered first is the sub moving to xmax in the current box with the current power. If the sub is only moving half the xmax with the current power and more power will push it to xmax then it would be equivalent to adding another sub. (Not taking power compression and such into account of course) On the other hand if the sub is already reaching xmax more power is pointless. -
I was referring to Scott's post about break in.
-
Read the last post in this thread.
-
Black bear trying to steal a snack...
Quentin Jarrell replied to Quentin Jarrell's topic in Photography
I had a few little Debbies, a few chips, and what not in there. They are always moving this time of year but I've never seen one stay around. They almost always get pissed or run off. She stuck around for a good 30 min. The truck was about 30 feet from my front doorstep. -
-
Black bear trying to steal a snack...
Quentin Jarrell replied to Quentin Jarrell's topic in Photography