NB50

There should be a time limit on threads with polls so they stop being bumped like a week after the thread goes inactive. So if someone votes on it after its been inactive for so long it doesn't bump the thread up.

You"d be super crispy when you seen him too.

Doom > all.

What kind of vehicles are these setups in?

That box won't be big enough for an 18" sub.

I'm not arguing that it won't rise, If you read my post it is that it won't drop. In an indirect way I even mentioned heat by saying "power applied". I'm not understanding your confusion and hostility.

Julian did. And while your borrowing your DMM from the electrical engineer ask them how to use it, can't measure resistance with power applied in a circuit. Have you taken impedance drop due to playing below tuning into consideration? No, No, No. and one more No.

Have you taken impedance drop due to playing below tuning into consideration? No, No, No. and one more No. What? Impedance rises before and after tuning. Pick up Loud speaker Design cookbook or WinISD and look at some resistance / frequency graphs. Also a speakers impedance is never going to drop below its measured/rated impedance especially with power applied (unless the speaker fails). OP do not count on impedance rise, set gains accordingly, use a different amplifier, or use a different speaker.

You kinda answered your own question. The whole port area and box volume are guidelines. Port area is determined by what speakers you are using.

Definitely, I had a tab using 25% CPU usage all that windows told me was it was chrome. Chrome told me exactly which tab it was.

Impious, RF isn't doing the normal rating scheme, they are rating full power (1500W) into both 2ohm and 1ohm. http://www.rockfordf...en_US&p_status=

Huh.. I didn't know chrome had its own task manager... pretty sweet and handy.

http://www.soundsolutionsaudio.com/forum/topic/45869-merlin-md-21-dcon-s4-package-deals/ /thread

These are very simplistic examples, there is a lot more to it but it gives the example of power distribution. In circuit one there is four 4 ohm speakers in series on each branch of the parallel circuit. that would give you 16ohms per branch with two wired in parallel it presents a 8 ohm load to the power source. Using ohms law E=I*R, E = voltage, I = current, R = resistance 120v/8ohms = 15A. There is 15 amps of current being provided to the circuit. Being that both branches are 16 ohms you can easily see that there is 7.5 amps per branch 120v/16 = 7.5A. So taking the 7.5A per branch you can calculate the voltage drop for each load 7.5 * 4 = 30V. Four loads of 30V voltage drops = 120V (voltage drops must add up to supply voltage). So each load in the circuit is droping the same voltage and seeing the same current so they are seeing the same power P=V*I, 30*7.5=225W each speaker is receiving 225W. In circuit 2 there is four 4 ohm resistors in parallel with 3 4 ohm resistors. Branch of four = 16 ohms the branch of 3 = 12 ohms paralleled together = 6.85 ohms. So 120V / 6.85ohms = 17.5A in the total circuit. Branch with 4 loads = 120 / 16 = 7.5A of current for the branch. With 30V of voltage drop over each load each load is seeing 225W in the branch with 4 loads. Branch with 3 loads = 120 / 12 = 10A of current, so 10A*4ohm = 40V of drop. 40V * 10A = 400W of power to each driver. I may have missed something but I dont think I did.

Sorry if I confused you a bit, give me a little bit and I'll draw up an example of both : even # of speakers on parallel legs and odd # of speakers on parallel legs.

Current follows the path of least resistance, so if impedance is the same, power is divided equally So if I have 7 4ohm speakers 3 in series and 4 in series then those lines parallel they all receive the same power. No, but I think that you knew that. The voltage is equal across each major parallel segment of the circuit. The current is constant through each series portion. Fairly simple math using Ohm's Law can give you the power to each load in the circuit as long as you know the load and voltage and how it is all wired together. BTW, 12 tweets on a single amp is completely stupid and could not have sounded like anything other than noise. That said, back in the day, Speaker Warehouse (JL Audio) built "the Blazer" that had 37 speakers including 8 10w5s wired to a single PPI 2-channel amp. It won 4 consecutive IASCA titles IIRC. Yes I know, just a little ribjabbin.

Current follows the path of least resistance, so if impedance is the same, power is divided equally So if I have 7 4ohm speakers 3 in series and 4 in series then those lines parallel they all receive the same power.

Absolutely insane deal here. Very great deal to add some low end on the cheap.

The ZX2500 isn't rated for a 1ohm load nor have I read of it being to stable at that load. So you would have to get D2 coils and wire it to 2 ohms but to answer your question the power is divided between the woofers. If your amp does 2500W @ 2 ohms and its wired to take advantage of that 2 woofers would get 1250w each. 4 woofers would get 625W each.

hmm ok so i wire the amp at 1 ohm and the dual 1 ohm BTL will get 2000w RMS, and i wire the amp at 1 ohm for the dual 2 ohm BTL and i get 4000w RMS? No, think of each coil only being rated for 1000w rms (which isn't necessarily true but in your case it will be fine.) No matter what load you wire it to, the speaker is going to be able to handle the same amount of power.

Top Gear usa edition premiers tonight.

Depends on the amplifier, the sub is only rated at 2000w rms.

I hope the poop isn't dried up an crusty when it gets there. Be really great if its still ewy gooey fresh.

Sub OD = Sub Outer Diameter Cut ID = Cut out diameter Displacement is how much volume is taken up by the woofer. Dual 1 ohm is two 1 ohm coils wired to 2 ohms or .5 ohms. Dual 2 ohm is two 2 ohm coils wired to 4 ohms or 1 ohm.