ssh

Happy Birthday Michael!

Guess it makes you appreciative that you don't own it.

I'll take one please. Have you seen the volvette?

http://www.youtube.com/watch?v=9kufacVXlSc#t=26

So they're suggesting 40hz tuning--kinda shitty. Is this for daily? 0.16 ft^3 per sub for displacement is good.

Use ifttt.com to setup a "recipe" and it'll search your craigslist with keywords and email / text you when a post meets your Criteria. I used it for finding a place near campus, so within 15min of a new listing came up I knew about it. wow this is cool. looking to buy an xbone sometime soon. You can do a ton of other shit with the site also. Might try searching "ifttt recipes," or "ifttt projects"

Gotta love reddit, this guy gets fucked by dealership see here: http://forums.themustangsource.com/f804/ford-dealership-abuse-532026/ Shit goes viral and now everyone knows about it, dealership's facebook blown up with posts about it: https://www.facebook.com/sawgrass.ford

You need to give more information. One can't recommend some amount of port area without making reference to the tuning (and to a somewhat lesser extent power). Those dimensions alone are meaningless. Are they internal or external dimensions? If external, what wood thickness are you using? Don't forget to account for displacement of a double baffle if using one, the speakers themselves, bracing, etc. Until we know the volume we can't calculate the port.

Do you go out of nostalgia? I went last year since a friend wanted to go and I don't understand what attracts adults / non-parents there.

I think you can set it up for eBay also.

Use ifttt.com to setup a "recipe" and it'll search your craigslist with keywords and email / text you when a post meets your Criteria. I used it for finding a place near campus, so within 15min of a new listing came up I knew about it.

Note that the above equation for port length is not taking port displacement into account.E.g. arbitrary values but say you have box volume 2 ft^3, port area 20 in^2, tuning 30hz, port length 25" The above values for the port and tuning are based upon a box volume of 2 ft^3, but the port itself is displacing (20 in^2 x 25in)*1ft^3/1728in^3 is 0.29 ft^3 so the net volume is now 1.7 ft^3 since the volume is actually less than what was used for calculation the actual tuning will be higher than 30hz. So you have to either play around with the numbers until you end up with the volume, tuning, and port length needed, or you simply add the port volume to the box volume and come up with new box dimensions (if you have the space), you can also calculate it here: http://box.bitpusher.in/enclosure/?page=portlength Also don't forget to account for the thickness of the port depending on the enclosure it may or may not be negligible. Alright well now I am a bit confused. I used the given formula for using port area and got 57.8" of port length when using the 3 cu ft and 74 in2 of port area. The part I am confused about is where in the formula am I looking to see the reduction in volume. I see where it is converting it to cubic inch but not changing the overall volume. I was initially under the impression that I would need to use the net volume. Sorry for the newb question but up until now I was relying on the Torres calculator. I just want to make sure I get the tuning length right. I'm a little confused by your question so I'll start from the very beginning. If you have a box 10" x 20" x 15" = 3000 in^3 or 3000 in^3 * (1 ft^3 / 1728 in^3) = 1.74 ft^3 your enclosure volume isn't 1.74 ft^3 because you need to account for the wood thickness. So say you used 3/4" then 10-0.75 x 20-0.75 x 15-0.75 = 2537 in^3 = 1.47 ft^3. Anything inside the enclosure displaces volume, so if you put a 2 liter soda bottle inside the enclosure then you need to subtract that volume (2 liters) from the enclosure volume. Obviously you wouldn't put a soda bottle in, but you get the idea? Anything inside displaces volume and that volume must be accounted for. When you mount the subs they displace volume, something around 0.15 ft^3 depending on the size and make, etc. So you have your measurements of the enclosure and account for the wood thickness, double baffle, speaker displacements, bracing displacement, and than you finally end up with a "net" volume. This volume is what you use with the equation posted above, the result of the equation is a port area of x, port length of y, and a port tuning of z for that amount of enclosure volume. So if you used an external port outside of the enclosure than you would simply make a port with area x, length y, you'd end up with z tuning, and you're done--that's it. The problem is if you use the equation to calculate your port length, area, and tuning based upon 3 ft^3 volume AND then you stick that port inside the enclosure, now the enclosure volume isn't 3 ft^3, it's 3 ft^3 - the volume of the port. The true and final net volume of the enclosure is less and thus the port tuning ends up being higher if you do the calculation again. If you use the above equation you either need to: design the enclosure in two parts so to speak where one is the net volume you're striving for and the rest is the port then put the two together so it fits the space in your vehicle. OR use the equation, find the port length, area, tuning, etc. Calculate the port volume, subtract it from the original volume you used to do the port calculations, do the port calculations again with the new net volume and use the same port length and you'll find out what the actual tuning is (it'll be higher). Then incrementally increase the port length, recalculate the port volume, subtract it from the enclosure volume, and input this into the equation again, now the tuning will be decreasing, and you can repeat this step until you end up with the correct port length that gives you tuning you originally wanted. I know this might sound complicating, but it's actually very simple. If you still need help post your math and I'll explain it. Alternatively you can use this calculator http://box.bitpusher.in/enclosure/?page=portlength which uses the exact same equation posted above but it will automatically do the latter steps to account for the port volume as long as you checkmark "Internal Port."

Sort of like asking me if I own a knife. Although, immersion circulator may be a more appropriate term here Yeah haha. I'm thinking of getting one since I'm no chief and it'll probably easier for me to cook steaks and shit without fucking anything up. At least that's my guess. No Maillard Some things are nice done that way, I prefer a hybrid. Keep meaning to DIY one as it is really easy in particular since I have a Rocks BBQ controller and it doesn't care if it controls a water heater or a fan. Isn't that what a mini blowtorch is for?

Sort of like asking me if I own a knife. Although, immersion circulator may be a more appropriate term here Yeah haha. I'm thinking of getting one since I'm no chief and it'll probably easier for me to cook steaks and shit without fucking anything up. At least that's my guess.

Note that the above equation for port length is not taking port displacement into account. E.g. arbitrary values but say you have box volume 2 ft^3, port area 20 in^2, tuning 30hz, port length 25" The above values for the port and tuning are based upon a box volume of 2 ft^3, but the port itself is displacing (20 in^2 x 25in)*1ft^3/1728in^3 is 0.29 ft^3 so the net volume is now 1.7 ft^3 since the volume is actually less than what was used for calculation the actual tuning will be higher than 30hz. So you have to either play around with the numbers until you end up with the volume, tuning, and port length needed, or you simply add the port volume to the box volume and come up with new box dimensions (if you have the space), you can also calculate it here: http://box.bitpusher.in/enclosure/?page=portlength Also don't forget to account for the thickness of the port depending on the enclosure it may or may not be negligible.

Word I'll stop there first then go to a mf.

Anyone cook by sous vide?

http://www.wired.co.uk/news/archive/2014-07/31/nasa-validates-impossible-space-drive Hmm

Get like ten or fifteen.

Sounds good, thanks. I'll probably check out what Costco has too.

Or do I hate people visiting? No I'm just on a budget. I'm sure my current mattress was cheap as fuck and I sleep fine on it, but I don't remember what I got and don't have the tags. I know this doesn't sound like the thing to be cheap on considering the amount of time we spend on it, but I'm in college. :shrugs:

Matt, I'm buying a cheap mattress pretty soon, as in a hundred bucks or so. I'm guessing at that price point they're all the same and shouldn't be overly concerned about brand x over brand y?

R would be in inches. From the above book.